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1. Count the number of heads and tails. 2. Find the probability of each outcome. 3. Calculate the total probability. 4. Find the probability that at least 2 tails occur. 1. There are a total of heads and tails, so the probability is 1/2. 2. The probability of each outcome is: heads: 0.5 tails: 0.5 3. The total probability is: heads: 0.25 tails: 0.75 4. The probability that at least 2 tails occur is: 0.99999995
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Question 5 fair coin is tossed 24 times. What is the probability that at most 23 tails occur? 0.99999851 b 0.00000149 0.99999994 0.00000143 0.00000006 None of the above_
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We are provided that a fair coin is tossed 24 times and we are asked to find the probability that a tale will occur at most 23 times. A tail occurs by X. The p of X is less than or equal to 23 since it is a fair coin and the property that a tail occurs is equal to 1/2 that is half. One -2 of X is equal to 24 so we can calculate P of X which is less than or equal to 23, Time's off feet to the part of Okay, times 1 -7 to the part of N-K. p of X is less than or equal to 23 24 Ps one over to whole part 24, 1 -2 is 1/6. We get one over to the whole of part 24, which is zero. We get a single one. The part of 24 that is 0.000 000 is referred to as C24. We get zero point, which is approximately equal to zero triple nine and nine ft, if we subtract this half the part of zero. The options that we are provided with are A, B, C,,,,,,, and F. We obtained option C since our answer was zero point triple nine triple 994 matches.