Educative Answers Team
The concept of super keyword comes with the idea of inheritance in Java. Suppose you have a member variable or method of the same name in the derived class as you do in the base class.
When referring to that variable/method, how would the program know which one are you referring to; the base class or the derived class?
This is where super comes into play. The super keyword in Java acts like a reference variable to the parent class.
It’s mainly used when we want to access a variable, method, or constructor in the base class, from the derived class.
Let’s have a look at some examples to understand how exactly the super keyword works.
Examples
1. Accessing base class variables
When we have the data members of the same name in both the base and derived class, we can use the super keyword to access the base class member, data, in the derived class.
The snippet below shows how to do this:
// Base Class
class Base {
int num = 30;
}
// Derived Class
class Derived extends Base {
int num = 20;
void callThis() {
// print `num` of both classes
System.out.println("Base `num`: " + super.num);
System.out.println("Derived `num`: " + num);
}
}
/* Driver Routine */
class Test {
public static void main(String[] args) {
Derived temp = new Derived();
temp.callThis();
}
}
2. Invoking base class method
When the name of a function if the same in both the base and derived class, the super keyword can be used to invoke the base class function in the derived class.
The snippet below shows how to do this:
// Base Class
class Base {
void display(){
System.out.println("Base Class");
}
}
// Derived Class
class Derived extends Base {
// invoke `display()` method for both the classes
void callThis(){
super.display();
display();
}
void display(){
System.out.println("Derived Class");
}
}
/* Driver Routine */
class Test {
public static void main(String[] args) {
Derived temp = new Derived();
temp.callThis();
}
}
3. Invoking base class constructor
The super keyword can also be used to invoke the parent class constructor, both parameterized and empty, in the derived class.
// Base Class
class Base {
Base(){
System.out.println("Base Class Constructor");
}
}
// Derived Class
class Derived extends Base {
// invoke `display()` method for both the classes
Derived(){
super();
System.out.println("Derived Class Constructor");
}
}
/* Driver Routine */
class Test {
public static void main(String[] args) {
Derived temp = new Derived();
}
}
RELATED TAGS
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inheritance
classes
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The super keyword in Java is used in subclasses to access superclass members (attributes, constructors and methods).
Before we learn about the super keyword, make sure to know about Java inheritance.
Uses of super keyword
- To call methods of the superclass that is overridden in the subclass.
- To access attributes (fields) of the superclass if both superclass and subclass have attributes with the same name.
- To explicitly call superclass no-arg (default) or parameterized constructor from the subclass constructor.
Let’s understand each of these uses.
1. Access Overridden Methods of the superclass
If methods with the same name are defined in both superclass and subclass, the method in the subclass overrides the method in the superclass. This is called method overriding.
Example 1: Method overriding
class Animal { // overridden method public void display(){ System.out.println("I am an animal"); } } class Dog extends Animal { // overriding method @Override public void display(){ System.out.println("I am a dog"); } public void printMessage(){ display(); } } class Main { public static void main(String[] args) { Dog dog1 = new Dog(); dog1.printMessage(); } }Output
I am a dogIn this example, by making an object dog1 of Dog class, we can call its method printMessage() which then executes the display() statement.
Since display() is defined in both the classes, the method of subclass Dog overrides the method of superclass Animal. Hence, the display() of the subclass is called.
What if the overridden method of the superclass has to be called?
We use super.display() if the overridden method display() of superclass Animal needs to be called.
Example 2: super to Call Superclass Method
class Animal { // overridden method public void display(){ System.out.println("I am an animal"); } } class Dog extends Animal { // overriding method @Override public void display(){ System.out.println("I am a dog"); } public void printMessage(){ // this calls overriding method display(); // this calls overridden method super.display(); } } class Main { public static void main(String[] args) { Dog dog1 = new Dog(); dog1.printMessage(); } }Output
I am a dog I am an animalHere, how the above program works.
2. Access Attributes of the Superclass
The superclass and subclass can have attributes with the same name. We use the super keyword to access the attribute of the superclass.
Example 3: Access superclass attribute
class Animal { protected String type="animal"; } class Dog extends Animal { public String type="mammal"; public void printType() { System.out.println("I am a " + type); System.out.println("I am an " + super.type); } } class Main { public static void main(String[] args) { Dog dog1 = new Dog(); dog1.printType(); } }Output:
I am a mammal I am an animalIn this example, we have defined the same instance field type in both the superclass Animal and the subclass Dog.
We then created an object dog1 of the Dog class. Then, the printType() method is called using this object.
Inside the printType() function,
- type refers to the attribute of the subclass Dog.
- super.type refers to the attribute of the superclass Animal.
Hence, System.out.println("I am a " + type); prints I am a mammal. And, System.out.println("I am an " + super.type); prints I am an animal.
3. Use of super() to access superclass constructor
As we know, when an object of a class is created, its default constructor is automatically called.
To explicitly call the superclass constructor from the subclass constructor, we use super(). It's a special form of the super keyword.
super() can be used only inside the subclass constructor and must be the first statement.
Example 4: Use of super()
class Animal { // default or no-arg constructor of class Animal Animal() { System.out.println("I am an animal"); } } class Dog extends Animal { // default or no-arg constructor of class Dog Dog() { // calling default constructor of the superclass super(); System.out.println("I am a dog"); } } class Main { public static void main(String[] args) { Dog dog1 = new Dog(); } }Output
I am an animal I am a dogHere, when an object dog1 of Dog class is created, it automatically calls the default or no-arg constructor of that class.
Inside the subclass constructor, the super() statement calls the constructor of the superclass and executes the statements inside it. Hence, we get the output I am an animal.
The flow of the program then returns back to the subclass constructor and executes the remaining statements. Thus, I am a dog will be printed.
However, using super() is not compulsory. Even if super() is not used in the subclass constructor, the compiler implicitly calls the default constructor of the superclass.
So, why use redundant code if the compiler automatically invokes super()?
It is required if the parameterized constructor (a constructor that takes arguments) of the superclass has to be called from the subclass constructor.
The parameterized super() must always be the first statement in the body of the constructor of the subclass, otherwise, we get a compilation error.
Example 5: Call Parameterized Constructor Using super()
class Animal { // default or no-arg constructor Animal() { System.out.println("I am an animal"); } // parameterized constructor Animal(String type) { System.out.println("Type: "+type); } } class Dog extends Animal { // default constructor Dog() { // calling parameterized constructor of the superclass super("Animal"); System.out.println("I am a dog"); } } class Main { public static void main(String[] args) { Dog dog1 = new Dog(); } }Output
Type: Animal I am a dogThe compiler can automatically call the no-arg constructor. However, it cannot call parameterized constructors.
If a parameterized constructor has to be called, we need to explicitly define it in the subclass constructor.
Note that in the above example, we explicitly called the parameterized constructor super("Animal"). The compiler does not call the default constructor of the superclass in this case.