What time will be required for a sum of money to double itself at 5% simple interest?

Solution:

Let the principal amount = Rs. 100

∴ Amount(A) = 100 x 2 = Rs. 200

∴ SI = A - P = 200 - 100 = Rs. 100

Rate (R) = 8% p.a

∴ TIme = \frac{SI\times100}{P\times R}=\frac{100\times100}{100\times8}=\frac{25}{2}=12\frac{1}{2}years

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Solution

Let sum of money be P=100
Interest per annum =10%
amount = 2× 100 = 200
simple interest = 200 - 100 = 100
Since, SI=PTR100
T=100×SIPR
=100×100100×10
t=10 years.


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In how many years will a sum of money double itself at 10% per annum simple interest?

  1. 4 years
  2. 8 years
  3. 10 years
  4. 6 years

Answer (Detailed Solution Below)

Option 3 : 10 years

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Given:

the sum of money doubles itself.

Rate = 10% 

Concept used:

 S.I. = PRT/100

Amount = P + SI

Calculation:

Amount = 2P = P + P

Let the Principal be 100, then Simple Interest = 100

⇒ 100 = (100 × 10 × T)/100

⇒ T = 10 years

∴ Time taken is 10 years.

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How many years will a sum of money double itself at the rate of 5% per annum?

So time required is 10 years.

In what time will a sum of money double itself at 5% pa C?

Answer: It takes 14.2 years for the amount to double itself.

In what time will a sum of money double itself at 5% CI payable half yearly?

So, a sum of money will double in 14 years.

What time will be required for a sum of money to double itself at simple rate interest is 8% pa?

⇒T=1008=12.5 years.

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