A sum of money becomes double in 20 years at simple interest in how many years will it be triple

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Solution

Let sum of money be P=100Interest per annum =10% amount = 2× 100 = 200 simple interest = 200 - 100 = 100Since, SI=PTR100⇒T=100×SIPR=100×100100×10∴t=10 years.

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A. 8 years

B. 10 years

C. 12 years

D. 14 years

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let principal = P}} \cr & \therefore {\text{amount = 3P}} \cr & {\text{Interest = 3P}} - {\text{P}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 2P}} \cr & {\text{According to the question,}} \cr & {\text{2P = }}\frac{{{\text{P}} \times {\text{R}} \times {\text{20}}}}{{100}} \cr & \Rightarrow {\text{R = 10% }} \cr} $$
Let after t years it will become double
$$\eqalign{ & {\text{Hence,}} \cr & {\text{Interest = 2P}} - {\text{P = P}} \cr & \Rightarrow {\text{P = }}\frac{{{\text{P}} \times 10 \times {\text{t}}}}{{100}} \cr & \Rightarrow {\text{t = 10 years}} \cr} $$

Given that, the sum of money triples itself in 20 years

∴ P + I = 3P

∴ I = 2P

and T = 20 years

Now simple interest I = `"PRT"/100`

∴ 2P = `("P" xx "R" xx 20)/100`

∴ R = 10

∴ Rate of interest = 10% per annum

The time period is to be calculated for the condition that the sum doubles itself i.e. for the condition

P + I = 2P

i.e. I = P

i.e. `("P" xx "R" xx "T")/100 = "P"`

∴ `(10 xx "T")/100 = 1`

∴ T = 10

∴ The sum will become double of itself in 10 years.

A sum of money at simple interest doubles in 10 years. In how many years, at the same rate, will it be tripled?

This question was previously asked in

UPTET 2018 Paper-1 (Hindi - English/Sanskrit) Hinglish Solution

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  1. 30 years
  2. 25 years
  3. 20 years
  4. 15 years

Answer (Detailed Solution Below)

Option 3 : 20 years

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10 Questions 10 Marks 7 Mins

GIVEN:

Amount = 2P

Time = 10 years

FORMULAE USED:

SI = (PRT/100) 

Amount = (PRT/100) + P

CALCULATION:

Amount = (PRT/100) + P

2P = (PR/10) + P 

⇒ P = (PR/10) 

⇒ R = 10%

According to question, Amount = 3P

3P = (10PT/100) + P 

⇒ 2P = (PT/10)

⇒ T = 20 years

 ∴ Time taken to triple the amount is 20 years.

A sum of money becomes double in 20 years at simple interest in how many years will it be triple
 

Interest = 2P - P = P = 100% of principle

Time = 10 year

Hence, rate = Interest/Time = 100/10 = 10%

New interest = 3P - P = 2P = 200% of principle

∴ Time = Interest/Rate = 200/10 = 20 Years

Last updated on Sep 21, 2022

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At what rate will a sum of money becomes double in 20 years at simple interest?

R=(P)(T)I=PI×201=1×201=0.05 per year or 5% per year interest.

How long would it take for money to triple in value at 20 a year simple interest?

Answer and Explanation: The calculated number of years it would take for money to triple in value at 20% per year simple interest is 10 .

At what rate of simple interest a sum of money would triple itself in 25 years?

R=12. 5%

How many years will it take for a sum of money to double at a simple interest rate of 5 %?

Thus, it will take 8 years.