Problems on coin toss probability are explained here with different examples. Show When we flip a coin there is always a probability to get a head or a tail is 50 percent. Suppose a coin tossed then we get two possible outcomes either a ‘head’ (H) or a ‘tail’ (T), and it is impossible to predict whether the result of a toss will be a ‘head’ or ‘tail’. The probability for equally likely outcomes in an event is: Number of favourable outcomes ÷ Total number of possible outcomes Total number of possible outcomes = 2 (i) If the favourable outcome is head (H). Number of favourable outcomes = 1. Therefore, P(getting a head) Number of favorable outcomes = 1/2. (ii) If the
favourable outcome is tail (T). Number of favourable outcomes = 1. Therefore, P(getting a tail) Number of favorable outcomes Word Problems on Coin Toss Probability: 1. A coin is tossed twice at random. What is the probability of getting (i) at least one head (ii) the same face? Solution: The possible outcomes are HH, HT, TH, TT. So, total number of outcomes = 4. (i) Number of favourable outcomes for event E = Number of outcomes having at least one head = 3 (as HH, HT, TH are having at least one head). So, by definition, P(F) = \(\frac{3}{4}\). (ii) Number of favourable outcomes for event E = Number of outcomes having the same face = 2 (as HH, TT are have the same face). So, by definition, P(F) = \(\frac{2}{4}\) = \(\frac{1}{2}\).
What is the probability of getting (i) three heads, (ii) two heads, (iii) one head, (iv) 0 head. Solution: Total number of trials = 175. Number of times three heads appeared = 21. Number of times two heads appeared = 56. Number of times one head appeared = 63. Number of times zero head appeared = 35. Let E1, E2, E3 and E4 be the events of getting three heads, two heads, one head and zero head respectively. (i) P(getting three heads) Number
of times three heads appeared = 21/175 = 0.12 (ii) P(getting two heads) Number of times two heads appeared = 56/175 = 0.32 (iii) P(getting one head) Number of times one head appeared = 63/175 = 0.36 (iv) P(getting zero head) Number of times zero head appeared = 35/175 = 0.20 Note: Remember when 3 coins are tossed randomly, the only possible outcomes are E2, E3, E4 and P(E1) + P(E2) + P(E3) + P(E4) = (0.12 + 0.32 + 0.36 + 0.20) = 1 3. Two coins are tossed randomly 120 times and it is found that two tails appeared 60 times, one tail appeared 48 times and no tail appeared 12 times. If two coins are tossed at random, what is the probability of getting (i) 2 tails, (ii) 1 tail, (iii) 0 tail Solution: Total number of trials = 120 Number of times 2 tails appear = 60 Number of times 1 tail appears = 48 Number of times 0 tail appears = 12 Let E1, E2 and E3 be the events of getting 2 tails, 1 tail and 0 tail respectively. (i) P(getting 2 tails) Number of times 2 tails appear = 60/120 = 0.50 (ii) P(getting 1 tail) Number
of times 1 tail appear = 48/120 = 0.40 (iii) P(getting 0 tail) Number of times no tail appear = 12/120 = 0.10 Note: Remember while tossing 2 coins simultaneously, the only possible outcomes are E1, E2, E3 and, P(E1) + P(E2) + P(E3) = (0.50 + 0.40 + 0.10) = 1  4. Suppose a fair coin is randomly tossed for 75 times and
it is found that head turns up 45 times and tail 30 times. What is the probability of getting (i) a head and (ii) a tail? Solution: Total number of trials = 75. Number of times head turns up = 45 Number of times tail turns up = 30 (i) Let X be the event of getting a head. P(getting a head) Number of times head turns up = 45/75 = 0.60 (ii) Let Y be the event of getting a tail. P(getting a tail) Number of times tail turns up = 30/75 = 0.40 Note: Remember when a fair coin is tossed and then X and Y are the only possible outcomes, and P(X) + P(Y) = (0.60 + 0.40) = 1 Probability Probability Random Experiments Experimental Probability Events in Probability Empirical Probability Coin Toss Probability Probability of Tossing Two Coins Probability of Tossing Three Coins Complimentary Events Mutually Exclusive Events Mutually Non-Exclusive Events Conditional Probability Theoretical Probability Odds and Probability Playing Cards Probability Probability and Playing Cards Probability for Rolling Two Dice Solved Probability Problems Probability for Rolling Three Dice 9th Grade Math From Coin toss Probability to HOME PAGE Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need. What is the probability of getting 3 tails in 5 tosses of a coin?Summary: If you flip a fair coin 5 times, the probability that you will get exactly 3 tails is 5/16.
What is the probability of tossing at least 3 heads out of 5 fair coin tosses?And that's of 32 equally likely possibilities. So the probability of getting exactly three heads-- well, you get exactly three heads in 10 of the 32 equally likely possibilities. So you have a 5/16 chance of that happening.
What is the probability of getting at least 3 tails?Answer: The probability of flipping a coin three times and getting 3 tails is 1/8. Let's solve this step by step.
When a coin is tossed 5 times what is the probability of getting 3 tails and 2 heads?Hence, the probability of getting 2 heads and 3 tails =3210=165.
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Find the probability that at least 3 tails occurred when 5 fair coins are tossed
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