In what time at 10% per annum simple interest a sum becomes 3 times of itself?

A. 8 years

B. 10 years

C. 12 years

D. 14 years

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let principal = P}} \cr & \therefore {\text{amount = 3P}} \cr & {\text{Interest = 3P}} - {\text{P}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 2P}} \cr & {\text{According to the question,}} \cr & {\text{2P = }}\frac{{{\text{P}} \times {\text{R}} \times {\text{20}}}}{{100}} \cr & \Rightarrow {\text{R = 10% }} \cr} $$
Let after t years it will become double
$$\eqalign{ & {\text{Hence,}} \cr & {\text{Interest = 2P}} - {\text{P = P}} \cr & \Rightarrow {\text{P = }}\frac{{{\text{P}} \times 10 \times {\text{t}}}}{{100}} \cr & \Rightarrow {\text{t = 10 years}} \cr} $$

If money is invested in a savings account earning $3.5 \%$ interest compounded yearly, how many years will pass until the money triples?

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Video Transcript

to find the compounding value off any amount. After a certain time. The formula is given as a is equal to p. Bun. Polis are by entered up, over and de there be is the principal value value off any amount. Where is the component value over the certain? Pdf and odd is given as 3.5%. Or we can say this a 0.0 titi five. But seeing so we can say like if suppose a principal amount is one in tow, X and the component amount will be three multiplied by X, where n is the time off component off the interest that is given nearly so that is one year now, using all these components in the function as three X is equal to x one pillars 0.35 debated way one minute to plague way one into de now solving this equation. Biggert as three is equal toe one plus zero point zero to the five upon one to the power de Now taking the log at both side, we can get as de multiplied way log one point 0 35 is equal to log today hands he will come out as lock three divided by log 1.2 d play. So this will come as approximate putting the value off. Look, three in a stranger from and this value off log this reveal get a 31 point nine years. So the value the time given 0.9 years, this money will be doubled having your interest off 3.5% component. And Willie. So this is the answer off the question.

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get a certain sum becomes 3 times at the rate of 8 per annum from screen.

[Solved] In what time a sum of money becomes 3 times of itself at sim

Let Principal be ‘p’ A sum of money becomes 3 times of itself, Amount, A = 3p SI = A - p = 2p ⇒ 2p = (p × 10 × t) /100 ⇒

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In what time a sum of money becomes 3 times of itself at simple interest rate of 10% per annum?

18 years 20 years 22 years 24 years

Answer (Detailed Solution Below)

Option 2 : 20 years

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Detailed Solution

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Let Principal be ‘p’

A sum of money becomes 3 times of itself,

Amount, A = 3p SI = A - p = 2p

⇒ 2p = (p × 10 × t) /100

⇒ 200/10 = t = 20 years

∴ In 20 years, a sum of money becomes 3 times of itself.

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A sum becomes three times itself at compound interest in eight years. In how many years will the sum become twenty seven times itself?

Click here👆to get an answer to your question ✍️ A sum becomes three times itself at compound interest in eight years. In how many years will the sum become twenty seven times itself?

Question

A sum becomes three times itself at compound interest in eight years. In how many years will the sum become twenty seven times itself?

A

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B

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C

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D

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Hard Open in App Solution Verified by Toppr

Correct option is A)

When interest is compounded, Amount A=P(1+

100 R ​ ) n Given, 3P=P(1+ 100 R ​ ) 8 =>3=(1+ 100 R ​ ) 8 --- (1) And, 27P=P(1+ 100 R ​ ) n =>27=(1+ 100 R ​ ) n =>3 3 =(1+ 100 R ​ ) n From eqn 1 =>((1+ 100 R ​ ) 8 ) 3 =(1+ 100 R ​ ) n =>(1+ 100 R ​ ) 24 =(1+ 100 R ​ ) n =>n=24

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स्रोत : www.toppr.com

In how many years will a certain sum become 3 times itself at 25 % per annum under simple interest?a 5b 8c 12d 6

In how many years will a certain sum become 3 times itself at 25 % per annum under simple interest?a 5b 8c 12d 6

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In how many years will a certain sum become 3 times itself at 25 % per annum under simple interest?a 5b 8c 12d 6

Question

In how many years will a certain sum become

3 times itself at 25 %

per annum under simple interest?

(a) 5 (b) 8 (c) 12 (d) 6 Open in App Solution If the sum be P . Amount ( A ) = 3 × P = 3 P Simple interest ( S . I ) = A − P = 3 P − P = 2 P Let the sum (P) be x

Then, simple interest

Rate of interest Time S . I = P × R × T 100 ⇒ T = 100 × S . I P × R = 100 × 2 x x × 25 = 4 × 2 = 8 Hence, 8 years required.

In what time at 10% per annum simple interest a sum becomes three times of itself?

∴ Time is 8 years. Was this answer helpful?

At what rate of interest does the amount becomes three times of the principal in 10 years?

∴ The rate of interest per annum is 20%.

In what time will a sum of money be multiplied three times at simple interest of 15% per annum?

So the answer for your question is 13Y and 4 months.

What will be the rate of interest so that a sum amounts to its three times in 25 years?

The rate of simple interest at which a sum of money becomes three times in 25 yr is. 8%