An unbiased coin is tossed three times. What is the probability of getting at least two heads?
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Answer (Detailed Solution Below)Option 4 : 1/2 Free Electric charges and coulomb's law (Basic) 10 Questions 10 Marks 10 Mins Formula Used: Probability = (Number of successful outcomes/Total number of outcomes) P(E) = (nE)/(nS), where nE = Number of events and nS = Number of sample space Calculation: When an unbiased coin is tossed three times, we'll get following cases; HHH, HHT, HTH, THH, HTT, THT, TTH, TTT Total possible outcomes = 8 Here, H = Head, T = Tail At least 2 heads outcomes = 4 P(E) = (nE)/(nS) = 4/8 = 1/2 ∴ Probability of getting at least two heads are 1/2. Latest Airforce Group X Updates Last updated on Nov 11, 2022 IAF Group X Provisional Select List List released for 01/2022 intake. The Indian Air Force (IAF) has also released the official notification for the IAF Group X (01/2023) on 7th November 2022. The selection of the candidates will depend on three stages which are Phase 1 (Online Written Test), Phase 2 ( DV, Physical Fitness Test, Adaptability Test I & II), and Phase 3 (Medical Examination). The exam is scheduled from 18th to 24th January 2023. The candidates who will qualify all the stages of selection process will be selected for the Air Force Group X posts & will receive a salary ranging of Rs. 30,000. This is one of the most sought jobs. Candidates can check the Airforce Group X Eligibility here. When two coins are tossed simultaneously then the possible outcomes obtained are {HH, HT, TH, and TT}. Here H denotes head and T denotes tail. Therefore, a total of 4 outcomes obtained on tossing two coins simultaneously. Number of favourable outcome(s) for no head is {TT} Number of favourable outcome(s) for one head is {HT, TH} Therefore, the event of getting at most one head has 3 favourable outcomes. These are TT, HT and TH. Therefore, the probability of getting at most one head = 3/4. A. $$\frac{{1}}{{4}}$$ B. 2 C. $$\frac{{3}}{{4}}$$ D. 1 Solution(By Examveda Team) Sample space (All [possible outcomes)S=(HH, HT, TH, TT) Total number of cases = 6*6 = 36 Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27 So Probability = 27/36 = 3/4 Question A No worries! We‘ve got your back. Try BYJU‘S free classes today! B Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses C No worries! We‘ve got your back. Try BYJU‘S free classes today! D No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Solution The correct option is BSuggest Corrections 1 Similar questions Q. Two unbiased coins are tossed
simultaneously. Find the probability of getting at most one head. Q. Two unbiased coins are tossed simultaneously. Find the probability of getting at least one head. Q. Three unbiased coins are simultaneously tossed. The probability of getting at the most 2 heads is Q. Two unbiased coins are tossed simultaneously. Find the probability of getting two heads. Q. Three unbiased coins are tossed simultaneously. Find the probability of getting at least two heads. View More When two unbiased coins are tossed the probability of getting at most one head is?∴, the probability of obtaining at most one head =43.
What is the probability of getting atleast one head if two unbiased coins are tossed?Coins are unbiased, so the probability of getting head or tail is 1/2.
When two unbiased coins are tossed the probability of getting 2 heads is?Probability of getting two heads or two tails = 2/4 = 1/2 . Hope helped!
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