This chapter reviews method parameters and local variables, as well as method overloading and method signature. Method overloading means two or more methods have the same name but have different parameter lists: either a different number of parameters or different types of parameters. When a method is called, the corresponding method is invoked by matching
the arguments in the call to the parameter lists of the methods. The name together with the number and types of a method's parameter list is called the signature of a method. The return type itself is not part of the signature of a method. When several methods have the same name, only one is picked by a method call. The types of the actual parameters in a method call are matched
with the types of the formal parameters of the methods. If an exact match cannot be made, then the actual parameters are converted to types that match the formal parameters if this can be done without potential loss of information. For example, the call matches this method declaration: public void processDeposit( int amount, int serviceCharge ) because the number and types of the actual parameters matches the number and types of the formal parameters. The signature of a method is:
The signatures of the methods in a class must be unique. For example, the signatures of the two
The names of the parameters are not part of the signature because parameter names are not visible outside of their scope. The return type is not part of the signature. The visibility modifier is not part of the signature. First things first Is it method overriding ? No , since to override a method you need to replicate the complete method signature as pointed out in Brian Agnew's answer and as I explain below. Is it overloading ? Yes , Method "add" has an overloaded implementation in Class B. Consider the following code:
So , the method in Class B in your code overloads the add method that it inherits from its parent Does it use Static Binding or Dynamic Binding ? This is what makes me conclude that OP is confused.It is static binding because it is a overloaded function. The only way to think of dynamic binding would have been in below scenario
Here , the parent class A has a contract that says , "I have an add behaviour for ints" . class B inherits this add behaviour and makes it more specific and at the same time also provides a new behaviour where it can add doubles. But class A has "no knowledge of this behaviour". So an object of class A "cannot" add doubles. To do that you need a more specific type of A object i.e. a B object. I need to do an assignment so i was strack in this Question in java When the same name is used for two or more methods in the same class, how does Java tell them apart? asked Oct 12, 2016 at 7:51
8 Java can tell apart different methods by their method signature. For example:
and
would be two different methods in Java, and can be called like this: Write("MineRocker"); Write("MineRocker", 1); A more in depth answer can be found here, https://docs.oracle.com/javase/tutorial/java/javaOO/methods.html answered Oct 12, 2016 at 8:14
When multiple methods exist within the same class with different method signatures this is?When multiple methods exist within the same class with the same name but different in signatures, this is known as what? It is called Method Overloading.
What is it called when the same method name is used by multiple methods with different parameters?Overloading occurs when two or more methods in one class have the same method name but different parameters.
When a class has more than one method with the same name but with different signatures it is called method overriding?Two methods with the same name and same class but the different signature is known as overloading and the method is known as an overloaded method while a method with the same name and same signature but in parent and child class is known as overriding.
When methods have the same name and different signatures this is called?Method overloading happens with methods with the same name but different signature.
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