When you have multiple methods with same name and different signature within the same class is known as?

This chapter reviews method parameters and local variables, as well as method overloading and method signature.

Method overloading means two or more methods have the same name but have different parameter lists: either a different number of parameters or different types of parameters. When a method is called, the corresponding method is invoked by matching the arguments in the call to the parameter lists of the methods. The name together with the number and types of a method's parameter list is called the signature of a method. The return type itself is not part of the signature of a method.

17. Method Signature

Answer:

  1. statement A calls processDeposit(int)
  2. statement B calls processDeposit(int, int)

Method Signature

When several methods have the same name, only one is picked by a method call. The types of the actual parameters in a method call are matched with the types of the formal parameters of the methods. If an exact match cannot be made, then the actual parameters are converted to types that match the formal parameters if this can be done without potential loss of information.

For example, the call

bobsAccount.processDeposit( 200, 25 );  //statement A

matches this method declaration:

public void  

 processDeposit( int amount, int serviceCharge )

because the number and types of the actual parameters matches the number and types of the formal parameters.

The signature of a method is:

      • Its name
      • The number and types of its parameters, in order

The signatures of the methods in a class must be unique. For example, the signatures of the two processDeposit methods are:

      • processDeposit( int )
      • processDeposit( int, int )

The names of the parameters are not part of the signature because parameter names are not visible outside of their scope.

The return type is not part of the signature. The visibility modifier is not part of the signature.


Question 17:

Say that a class has the following two methods:

    float chargePenalty( int amount ) { ... } int chargePenalty( int penalty ) { ... }

Do these methods have unique signatures?

First things first

Is it method overriding ?

No , since to override a method you need to replicate the complete method signature as pointed out in Brian Agnew's answer and as I explain below.

Is it overloading ?

Yes , Method "add" has an overloaded implementation in Class B.

Consider the following code:

class C{
    public static void main(String args[]){
        B a = new B();
        a.add(2 , 3);
        a.add(2.0 , 3.0);
    }
}

class A {

    public int add(int a , int b) {
        System.out.print("INT ");
        return a + b;
    }
}

class B extends A {
    public double add(double a , double b) {
        System.out.print("Double ");
        return a + b;
    }
}

OUTPUT : INT Double

So , the method in Class B in your code overloads the add method that it inherits from its parent

Does it use Static Binding or Dynamic Binding ?

This is what makes me conclude that OP is confused.It is static binding because it is a overloaded function. The only way to think of dynamic binding would have been in below scenario

class C{
    public static void main(String args[]){
        A a = new B();
        a.add(2.0 , 3.0);
    }
}

class A {

    public int add(int a , int b) {
        System.out.println("A : INT");
        return a + b;
    }
}

class B extends A {
    public int add(int a , int b) {
        System.out.println("B : INT");    
        return a + b;
    }
        
    public double add(double a , double b) {
        System.out.println("Double");
        return a + b;
    }   
}

Output : B : INT

Here , the parent class A has a contract that says , "I have an add behaviour for ints" . class B inherits this add behaviour and makes it more specific and at the same time also provides a new behaviour where it can add doubles. But class A has "no knowledge of this behaviour".

So an object of class A "cannot" add doubles. To do that you need a more specific type of A object i.e. a B object.

I need to do an assignment so i was strack in this Question in java

When the same name is used for two or more methods in the same class, how does Java tell them apart?

asked Oct 12, 2016 at 7:51

When you have multiple methods with same name and different signature within the same class is known as?

8

Java can tell apart different methods by their method signature.

For example:

public void Write(String Name) {
}

and

public void Write(String Name, int number) {
}

would be two different methods in Java, and can be called like this:

Write("MineRocker"); Write("MineRocker", 1);

A more in depth answer can be found here, https://docs.oracle.com/javase/tutorial/java/javaOO/methods.html

answered Oct 12, 2016 at 8:14

When you have multiple methods with same name and different signature within the same class is known as?

When multiple methods exist within the same class with different method signatures this is?

When multiple methods exist within the same class with the same name but different in signatures, this is known as what? It is called Method Overloading.

What is it called when the same method name is used by multiple methods with different parameters?

Overloading occurs when two or more methods in one class have the same method name but different parameters.

When a class has more than one method with the same name but with different signatures it is called method overriding?

Two methods with the same name and same class but the different signature is known as overloading and the method is known as an overloaded method while a method with the same name and same signature but in parent and child class is known as overriding.

When methods have the same name and different signatures this is called?

Method overloading happens with methods with the same name but different signature.