Which of the following keywords is used for creating objects in Java a create B Instanceof c new d return?

The instanceof operator tests to see if the prototype property of a constructor appears anywhere in the prototype chain of an object. The return value is a boolean value. Its behavior can be customized with Symbol.hasInstance.

Try it

Syntax

object instanceof constructor

Parameters

object

The object to test.

constructor

Constructor to test against.

Exceptions

TypeError

Thrown if constructor is not an object. If constructor doesn't have a @@hasInstance method, it must also be a function.

Description

The instanceof operator tests the presence of constructor.prototype in object's prototype chain. This usually means object was constructed with constructor.

// defining constructors
function C() {}
function D() {}

const o = new C();

// true, because: Object.getPrototypeOf(o) === C.prototype
o instanceof C;

// false, because D.prototype is nowhere in o's prototype chain
o instanceof D;

o instanceof Object; // true, because:
C.prototype instanceof Object; // true

// Re-assign `constructor.prototype`: you should
// rarely do this in practice.
C.prototype = {};
const o2 = new C();

o2 instanceof C; // true

// false, because C.prototype is nowhere in
// o's prototype chain anymore
o instanceof C;

D.prototype = new C(); // add C to [[Prototype]] linkage of D
const o3 = new D();
o3 instanceof D; // true
o3 instanceof C; // true since C.prototype is now in o3's prototype chain

Note that the value of an instanceof test can change if constructor.prototype is re-assigned after creating the object (which is usually discouraged). It can also be changed by changing object's prototype using Object.setPrototypeOf.

Classes behave in the same way, because classes also have the prototype property.

class A {}
class B extends A {}

const o1 = new A();
// true, because Object.getPrototypeOf(o1) === A.prototype
o1 instanceof A;
// false, because B.prototype is nowhere in o1's prototype chain
o1 instanceof B;

const o2 = new B();
// true, because Object.getPrototypeOf(Object.getPrototypeOf(o2)) === A.prototype
o2 instanceof A;
// true, because Object.getPrototypeOf(o2) === B.prototype
o2 instanceof B;

If constructor has a Symbol.hasInstance method, the method will be called in priority, with object as its only argument and constructor as this.

// This class allows plain objects to be disguised as this class's instance,
// as long as the object has a particular flag as its property.
class Forgeable {
  static isInstanceFlag = Symbol("isInstanceFlag");

  static [Symbol.hasInstance](obj) {
    return Forgeable.isInstanceFlag in obj;
  }
}

const obj = { [Forgeable.isInstanceFlag]: true };
console.log(obj instanceof Forgeable); // true

For bound functions, instanceof looks up for the prototype property on the target function, since bound functions don't have prototype.

class Base {}
const BoundBase = Base.bind(null, 1, 2);
console.log(new Base() instanceof BoundBase); // true

instanceof and multiple realms

JavaScript execution environments (windows, frames, etc.) are each in their own realm. This means that they have different built-ins (different global object, different constructors, etc.). This may result in unexpected results. For instance, [] instanceof window.frames[0].Array will return false, because Array.prototype !== window.frames[0].Array.prototype and arrays in the current realm inherit from the former.

This may not make sense at first, but for scripts dealing with multiple frames or windows, and passing objects from one context to another via functions, this will be a valid and strong issue. For instance, you can securely check if a given object is in fact an Array using Array.isArray(), neglecting which realm it comes from.

For example, to check if a Node is an SVGElement in a different context, you can use myNode instanceof myNode.ownerDocument.defaultView.SVGElement.

Examples

Using instanceof with String

The following example shows the behavior of instanceof with String objects.

const literalString = "This is a literal string";
const stringObject = new String("String created with constructor");

literalString instanceof String; // false, string primitive is not a String
stringObject instanceof String; // true

literalString instanceof Object; // false, string primitive is not an Object
stringObject instanceof Object; // true

stringObject instanceof Date; // false

Using instanceof with Date

The following example shows the behavior of instanceof with Date objects.

const myDate = new Date();

myDate instanceof Date; // true
myDate instanceof Object; // true
myDate instanceof String; // false

Objects created using Object.create()

The following example shows the behavior of instanceof with objects created using Object.create().

function Shape() {}

function Rectangle() {
  Shape.call(this); // call super constructor.
}

Rectangle.prototype = Object.create(Shape.prototype);

Rectangle.prototype.constructor = Rectangle;

const rect = new Rectangle();

rect instanceof Object; // true
rect instanceof Shape; // true
rect instanceof Rectangle; // true
rect instanceof String; // false

const literalObject = {};
const nullObject = Object.create(null);
nullObject.name = "My object";

literalObject instanceof Object; // true, every object literal has Object.prototype as prototype
({} instanceof Object); // true, same case as above
nullObject instanceof Object; // false, prototype is end of prototype chain (null)

Demonstrating that mycar is of type Car and type Object

The following code creates an object type Car and an instance of that object type, mycar. The instanceof operator demonstrates that the mycar object is of type Car and of type Object.

function Car(make, model, year) {
  this.make = make;
  this.model = model;
  this.year = year;
}
const mycar = new Car("Honda", "Accord", 1998);
const a = mycar instanceof Car; // returns true
const b = mycar instanceof Object; // returns true

Not an instanceof

To test if an object is not an instanceof a specific constructor, you can do:

if (!(mycar instanceof Car)) {
  // Do something, like:
  // mycar = new Car(mycar)
}

This is really different from:

if (!mycar instanceof Car) {
  // unreachable code
}

This will always be false. (!mycar will be evaluated before instanceof, so you always try to know if a boolean is an instance of Car).

Specifications

Specification
ECMAScript Language Specification
# sec-relational-operators

Browser compatibility

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See also

Which is the keyword used to create an object in Java?

Instantiation: The new keyword is a Java operator that creates the object. Initialization: The new operator is followed by a call to a constructor, which initializes the new object.

What Java keyword is used to create objects out of a class?

Instantiation: The new keyword is a Java operator that creates the object. As discussed below, this is also known as instantiating a class.

What keywords are used to create an object?

The correct answer is: (b) New. In Java, the ''new'' keyword is used to create an object, i.e., an instance of a class.

How do you create an object in Java?

To create an object of Main , specify the class name, followed by the object name, and use the keyword new :.
Example. Create an object called " myObj " and print the value of x: public class Main { int x = 5; public static void main(String[] args) { Main myObj = new Main(); System. ... .
Example. ... .
Second.java..