If you're seeing this message, it means we're having trouble loading external resources on our website. Show If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. PART C - The replication bubble and antiparallel elongation DNA replication always begins at an origin of replication. In bacteria, there is a single origin of replication on the circular chromosome, as shown in the image here. Beginning at the origin of replication, the two parental strands (dark blue) separate, forming a replication bubble. At each end of the replication bubble is a replication fork where the parental strands are unwound and new daughter strands (light blue) are synthesized. Movement of the replication forks away from the origin expands the replication bubble until two identical chromosomes are ultimately produced. Diagram showing DNA replication in a circular chromosome. For simplicity, the double-stranded DNA is shown as two concentric circles. There is one origin of replication, where the two parental strands, shown in dark blue, separate, forming a replication bubble. At each end of the replication bubble is a replication fork, indicated by a pink arrow, where the parental strands are unwound and new daughter strands, shown in light blue, are synthesized. The replication forks move away from the origin and expand the replication bubble. As the light blue strands elongate, the two double-stranded circles that are forming start to peel off from each other. The end result is two separate, identical daughter DNA molecules, each composed of one parental strand, dark blue, and one new strand, light blue. In this activity, you will demonstrate your understanding of antiparallel elongation at the replication forks. Keep in mind that the two strands in a double helix are oriented in opposite directions, that is, they are antiparallel. Drag the arrows onto the diagram below to indicate the direction that DNA polymerase III moves along the parental (template) DNA strands at each of the two replication forks. Arrows can be used once, more than once, or not at all. Solution : The `B` sample of `DNA` having hegher `T_(m)` must be having more `GC` content as compared to sample`A`, since `GC` base pair having three hydrogen bonds (as compared to `AT` base pair having only two hydrogen bonds) results in stronger bonding.
ProblemYou are given two samples of DNA, each of which m…Question: Problem 6 Easy DifficultyVideo Answer: Get the answer to your homework problem. Try Numerade free for 7 days Input your name and email to request the answer Numerade Educator Numerade Educator Like Report Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 AnswerRelated CoursesBiology
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0:00 The Central Dogma - Overview In biology, the central dogma is the idea that genetic information flow in cells is unidirectional, from DNA to RNA to protein, never in the reverse direction. The central dogma was first proposed by Francis Crick in 1958 as a summary of what was known about the flow of genetic information at the time, and has been repeatedly confirmed in the decades since its proposal. It is considered one of the fundamental principles of molecular biology, and underpins the modern understanding of the molecular basis of heredity.
0:00 DNA Structure and Function In molecular biology, DNA structure is the arrangement of atoms in a DNA molecule. DNA structure is dynamic; the structure of a DNA molecule changes as it replicates and as it interacts with other molecules. The structure of a DNA molecule may be considered on all length scales, from the level of individual nucleotides, to the level of entire chromosomes. Join Course Recommended Videos01:57 Figure $18-36$ shows the m… 03:05 The melting curve for the … 02:36 The "melting point&qu… 01:05 How is the melting curve o… 05:12 The complementary strands … 02:03 Melting Organic Compounds … 00:34 The adjoining illustration… Watch More Solved Questions in Chapter 18Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Video TranscriptNo transcript available |