Which of these method of class String is used to compare two String objects for their equality Isequal () equals () equals () Isequals ()?

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Object.Equals Method

• Reference

Definition

Determines whether two object instances are equal.

In this article

Overloads

Equals(Object)

Determines whether the specified object is equal to the current object.

public:
 virtual bool Equals(System::Object ^ obj);

public virtual bool Equals (object obj);

public virtual bool Equals (object? obj);

abstract member Equals : obj -> bool
override this.Equals : obj -> bool

Public Overridable Function Equals (obj As Object) As Boolean

Parameters

obj Object

The object to compare with the current object.

Returns

true if the specified object is equal to the current object; otherwise, false.

Examples

The following example shows a Point class that overrides the Equals method to provide value equality, and a Point3D class that is derived from Point. Because Point overrides Object.Equals(Object) to test for value equality, the Object.Equals(Object) method is not called. However, Point3D.Equals calls Point.Equals because Point implements Object.Equals(Object) in a manner that provides value equality.

using System;

class Point
{
   protected int x, y;

   public Point() : this(0, 0)
   { }

   public Point(int x, int y)
   {
      this.x = x;
      this.y = y;
   }

   public override bool Equals(Object obj)
   {
      //Check for null and compare run-time types.
      if ((obj == null) || ! this.GetType().Equals(obj.GetType()))
      {
         return false;
      }
      else {
         Point p = (Point) obj;
         return (x == p.x) && (y == p.y);
      }
   }

   public override int GetHashCode()
   {
      return (x << 2) ^ y;
   }

    public override string ToString()
    {
        return String.Format("Point({0}, {1})", x, y);
    }
}

sealed class Point3D: Point
{
   int z;

   public Point3D(int x, int y, int z) : base(x, y)
   {
      this.z = z;
   }

   public override bool Equals(Object obj)
   {
      Point3D pt3 = obj as Point3D;
      if (pt3 == null)
         return false;
      else
         return base.Equals((Point)obj) && z == pt3.z;
   }

   public override int GetHashCode()
   {
      return (base.GetHashCode() << 2) ^ z;
   }

   public override String ToString()
   {
        return String.Format("Point({0}, {1}, {2})", x, y, z);
    }
}

class Example
{
  public static void Main()
  {
     Point point2D = new Point(5, 5);
     Point3D point3Da = new Point3D(5, 5, 2);
     Point3D point3Db = new Point3D(5, 5, 2);
     Point3D point3Dc = new Point3D(5, 5, -1);

     Console.WriteLine("{0} = {1}: {2}",
                       point2D, point3Da, point2D.Equals(point3Da));
     Console.WriteLine("{0} = {1}: {2}",
                       point2D, point3Db, point2D.Equals(point3Db));
     Console.WriteLine("{0} = {1}: {2}",
                       point3Da, point3Db, point3Da.Equals(point3Db));
     Console.WriteLine("{0} = {1}: {2}",
                       point3Da, point3Dc, point3Da.Equals(point3Dc));
  }
}
// The example displays the following output:
//       Point(5, 5) = Point(5, 5, 2): False
//       Point(5, 5) = Point(5, 5, 2): False
//       Point(5, 5, 2) = Point(5, 5, 2): True
//       Point(5, 5, 2) = Point(5, 5, -1): False

type Point(x, y) =
    new () = Point(0, 0)
    member _.X = x
    member _.Y = y

    override _.Equals(obj) =
        //Check for null and compare run-time types.
        match obj with
        | :? Point as p ->
            x = p.X && y = p.Y
        | _ -> 
            false

    override _.GetHashCode() =
        (x <<< 2) ^^^ y

    override _.ToString() =
        $"Point({x}, {y})"

type Point3D(x, y, z) =
    inherit Point(x, y)
    member _.Z = z

    override _.Equals(obj) =
        match obj with
        | :? Point3D as pt3 ->
            base.Equals(pt3 :> Point) && z = pt3.Z
        | _ -> 
            false

    override _.GetHashCode() =
        (base.GetHashCode() <<< 2) ^^^ z

    override _.ToString() =
        $"Point({x}, {y}, {z})"

let point2D = Point(5, 5)
let point3Da = Point3D(5, 5, 2)
let point3Db = Point3D(5, 5, 2)
let point3Dc = Point3D(5, 5, -1)

printfn $"{point2D} = {point3Da}: {point2D.Equals point3Da}"
printfn $"{point2D} = {point3Db}: {point2D.Equals point3Db}"
printfn $"{point3Da} = {point3Db}: {point3Da.Equals point3Db}"
printfn $"{point3Da} = {point3Dc}: {point3Da.Equals point3Dc}"
// The example displays the following output:
//       Point(5, 5) = Point(5, 5, 2): False
//       Point(5, 5) = Point(5, 5, 2): False
//       Point(5, 5, 2) = Point(5, 5, 2): True
//       Point(5, 5, 2) = Point(5, 5, -1): False

Class Point
    Protected x, y As Integer
    
    Public Sub New() 
        Me.x = 0
        Me.y = 0
    End Sub
    
    Public Sub New(x As Integer, y As Integer) 
        Me.x = x
        Me.y = y
    End Sub 

    Public Overrides Function Equals(obj As Object) As Boolean 
        ' Check for null and compare run-time types.
        If obj Is Nothing OrElse Not Me.GetType().Equals(obj.GetType()) Then
           Return False
        Else
           Dim p As Point = DirectCast(obj, Point)
           Return x = p.x AndAlso y = p.y
        End If
    End Function 

    Public Overrides Function GetHashCode() As Integer 
        Return (x << 2) XOr y
    End Function

    Public Overrides Function ToString() As String
        Return String.Format("Point({0}, {1})", x, y)
    End Function
End Class

Class Point3D : Inherits Point
    Private z As Integer
    
    Public Sub New(ByVal x As Integer, ByVal y As Integer, ByVal z As Integer) 
        MyBase.New(x, y) 
        Me.z = Z
    End Sub

    Public Overrides Function Equals(ByVal obj As Object) As Boolean 
        Dim pt3 As Point3D = TryCast(obj, Point3D)
        If pt3 Is Nothing Then
           Return False
        Else
           Return MyBase.Equals(CType(pt3, Point)) AndAlso z = pt3.Z  
        End If
    End Function
    
    Public Overrides Function GetHashCode() As Integer 
        Return (MyBase.GetHashCode() << 2) XOr z
    End Function 
    
    Public Overrides Function ToString() As String
        Return String.Format("Point({0}, {1}, {2})", x, y, z)
    End Function
End Class 

Module Example
    Public Sub Main() 
        Dim point2D As New Point(5, 5)
        Dim point3Da As New Point3D(5, 5, 2)
        Dim point3Db As New Point3D(5, 5, 2)
        Dim point3Dc As New Point3D(5, 5, -1)
        
        Console.WriteLine("{0} = {1}: {2}", 
                          point2D, point3Da, point2D.Equals(point3Da))
        Console.WriteLine("{0} = {1}: {2}", 
                          point2D, point3Db, point2D.Equals(point3Db))        
        Console.WriteLine("{0} = {1}: {2}", 
                          point3Da, point3Db, point3Da.Equals(point3Db))
        Console.WriteLine("{0} = {1}: {2}", 
                          point3Da, point3Dc, point3Da.Equals(point3Dc))
    End Sub  
End Module 
' The example displays the following output
'       Point(5, 5) = Point(5, 5, 2): False
'       Point(5, 5) = Point(5, 5, 2): False
'       Point(5, 5, 2) = Point(5, 5, 2): True
'       Point(5, 5, 2) = Point(5, 5, -1): False

The Point.Equals method checks to make sure that the obj argument is not null and that it references an instance of the same type as this object. If either check fails, the method returns false.

The Point.Equals method calls the GetType method to determine whether the run-time types of the two objects are identical. If the method used a check of the form obj is Point in C# or TryCast(obj, Point) in Visual Basic, the check would return true in cases where obj is an instance of a derived class of Point, even though obj and the current instance are not of the same run-time type. Having verified that both objects are of the same type, the method casts obj to type Point and returns the result of comparing the instance fields of the two objects.

In Point3D.Equals, the inherited Point.Equals method, which overrides Object.Equals(Object), is invoked before anything else is done. Because Point3D is a sealed class (NotInheritable in Visual Basic), a check in the form obj is Point in C# or TryCast(obj, Point) in Visual Basic is adequate to ensure that obj is a Point3D object. If it is a Point3D object, it is cast to a Point object and passed to the base class implementation of Equals. Only when the inherited Point.Equals method returns true does the method compare the z instance fields introduced in the derived class.

The following example defines a Rectangle class that internally implements a rectangle as two Point objects. The Rectangle class also overrides Object.Equals(Object) to provide for value equality.

using System;

class Rectangle
{
   private Point a, b;

   public Rectangle(int upLeftX, int upLeftY, int downRightX, int downRightY)
   {
      this.a = new Point(upLeftX, upLeftY);
      this.b = new Point(downRightX, downRightY);
   }

   public override bool Equals(Object obj)
   {
      // Perform an equality check on two rectangles (Point object pairs).
      if (obj == null || GetType() != obj.GetType())
          return false;
      Rectangle r = (Rectangle)obj;
      return a.Equals(r.a) && b.Equals(r.b);
   }

   public override int GetHashCode()
   {
      return Tuple.Create(a, b).GetHashCode();
   }

    public override String ToString()
    {
       return String.Format("Rectangle({0}, {1}, {2}, {3})",
                            a.x, a.y, b.x, b.y);
    }
}

class Point
{
  internal int x;
  internal int y;

  public Point(int X, int Y)
  {
     this.x = X;
     this.y = Y;
  }

  public override bool Equals (Object obj)
  {
     // Performs an equality check on two points (integer pairs).
     if (obj == null || GetType() != obj.GetType()) return false;
     Point p = (Point)obj;
     return (x == p.x) && (y == p.y);
  }

  public override int GetHashCode()
  {
     return Tuple.Create(x, y).GetHashCode();
  }
}

class Example
{
   public static void Main()
   {
      Rectangle r1 = new Rectangle(0, 0, 100, 200);
      Rectangle r2 = new Rectangle(0, 0, 100, 200);
      Rectangle r3 = new Rectangle(0, 0, 150, 200);

      Console.WriteLine("{0} = {1}: {2}", r1, r2, r1.Equals(r2));
      Console.WriteLine("{0} = {1}: {2}", r1, r3, r1.Equals(r3));
      Console.WriteLine("{0} = {1}: {2}", r2, r3, r2.Equals(r3));
   }
}
// The example displays the following output:
//    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 100, 200): True
//    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
//    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False

type Point(x, y) =
    member _.X = x
    member _.Y = y

    override _.Equals(obj) =
        // Performs an equality check on two points (integer pairs).
        match obj with
        | :? Point as p ->
            x = p.X && y = p.Y
        | _ ->
            false
    
    override _.GetHashCode() =
        (x, y).GetHashCode()

type Rectangle(upLeftX, upLeftY, downRightX, downRightY) =
    let a = Point(upLeftX, upLeftY)
    let b = Point(downRightX, downRightY)
    
    member _.UpLeft = a
    member _.DownRight = b

    override _.Equals(obj) =
        // Perform an equality check on two rectangles (Point object pairs).
        match obj with
        | :? Rectangle as r ->
            a.Equals(r.UpLeft) && b.Equals(r.DownRight)
        | _ -> 
            false
        
    override _.GetHashCode() =
        (a, b).GetHashCode()

    override _.ToString() =
       $"Rectangle({a.X}, {a.Y}, {b.X}, {b.Y})"

let r1 = Rectangle(0, 0, 100, 200)
let r2 = Rectangle(0, 0, 100, 200)
let r3 = Rectangle(0, 0, 150, 200)

printfn $"{r1} = {r2}: {r1.Equals r2}"
printfn $"{r1} = {r3}: {r1.Equals r3}"
printfn $"{r2} = {r3}: {r2.Equals r3}"
// The example displays the following output:
//    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 100, 200): True
//    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
//    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False

Class Rectangle 
    Private a, b As Point
    
    Public Sub New(ByVal upLeftX As Integer, ByVal upLeftY As Integer, _
                   ByVal downRightX As Integer, ByVal downRightY As Integer) 
        Me.a = New Point(upLeftX, upLeftY)
        Me.b = New Point(downRightX, downRightY)
    End Sub 
    
    Public Overrides Function Equals(ByVal obj As [Object]) As Boolean 
        ' Performs an equality check on two rectangles (Point object pairs).
        If obj Is Nothing OrElse Not [GetType]().Equals(obj.GetType()) Then
            Return False
        End If
        Dim r As Rectangle = CType(obj, Rectangle)
        Return a.Equals(r.a) AndAlso b.Equals(r.b)
    End Function

    Public Overrides Function GetHashCode() As Integer 
        Return Tuple.Create(a, b).GetHashCode()
    End Function 

    Public Overrides Function ToString() As String
       Return String.Format("Rectangle({0}, {1}, {2}, {3})",
                            a.x, a.y, b.x, b.y) 
    End Function
End Class 

Class Point
    Friend x As Integer
    Friend y As Integer
    
    Public Sub New(ByVal X As Integer, ByVal Y As Integer) 
        Me.x = X
        Me.y = Y
    End Sub 

    Public Overrides Function Equals(ByVal obj As [Object]) As Boolean 
        ' Performs an equality check on two points (integer pairs).
        If obj Is Nothing OrElse Not [GetType]().Equals(obj.GetType()) Then
            Return False
        Else
           Dim p As Point = CType(obj, Point)
           Return x = p.x AndAlso y = p.y
        End If
    End Function 
    
    Public Overrides Function GetHashCode() As Integer 
        Return Tuple.Create(x, y).GetHashCode()
    End Function 
End Class  

Class Example
    Public Shared Sub Main() 
        Dim r1 As New Rectangle(0, 0, 100, 200)
        Dim r2 As New Rectangle(0, 0, 100, 200)
        Dim r3 As New Rectangle(0, 0, 150, 200)
        
        Console.WriteLine("{0} = {1}: {2}", r1, r2, r1.Equals(r2))
        Console.WriteLine("{0} = {1}: {2}", r1, r3, r1.Equals(r3))
        Console.WriteLine("{0} = {1}: {2}", r2, r3, r2.Equals(r3))
    End Sub 
End Class 
' The example displays the following output:
'    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 100, 200): True
'    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
'    Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False

Some languages such as C# and Visual Basic support operator overloading. When a type overloads the equality operator, it must also override the Equals(Object) method to provide the same functionality. This is typically accomplished by writing the Equals(Object) method in terms of the overloaded equality operator, as in the following example.

using System;

public struct Complex
{
   public double re, im;

   public override bool Equals(Object obj)
   {
      return obj is Complex && this == (Complex)obj;
   }

   public override int GetHashCode()
   {
      return Tuple.Create(re, im).GetHashCode();
   }

   public static bool operator ==(Complex x, Complex y)
   {
      return x.re == y.re && x.im == y.im;
   }

   public static bool operator !=(Complex x, Complex y)
   {
      return !(x == y);
   }

    public override String ToString()
    {
       return String.Format("({0}, {1})", re, im);
    }
}

class MyClass
{
  public static void Main()
  {
    Complex cmplx1, cmplx2;

    cmplx1.re = 4.0;
    cmplx1.im = 1.0;

    cmplx2.re = 2.0;
    cmplx2.im = 1.0;

    Console.WriteLine("{0} <> {1}: {2}", cmplx1, cmplx2, cmplx1 != cmplx2);
    Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2));

    cmplx2.re = 4.0;

    Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1 == cmplx2);
    Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2));
  }
}
// The example displays the following output:
//       (4, 1) <> (2, 1): True
//       (4, 1) = (2, 1): False
//       (4, 1) = (4, 1): True
//       (4, 1) = (4, 1): True

[<Struct; CustomEquality; NoComparison>]
type Complex =
    val mutable re: double
    val mutable im: double

    override this.Equals(obj) =
        match obj with 
        | :? Complex as c when c = this -> true
        | _ -> false 

    override this.GetHashCode() =
        (this.re, this.im).GetHashCode()

    override this.ToString() =
        $"({this.re}, {this.im})"

    static member op_Equality (x: Complex, y: Complex) =
        x.re = y.re && x.im = y.im

    static member op_Inequality (x: Complex, y: Complex) =
        x = y |> not

let mutable cmplx1 = Complex()
let mutable cmplx2 = Complex()

cmplx1.re <- 4.0
cmplx1.im <- 1.0

cmplx2.re <- 2.0
cmplx2.im <- 1.0

printfn $"{cmplx1} <> {cmplx2}: {cmplx1 <> cmplx2}"
printfn $"{cmplx1} = {cmplx2}: {cmplx1.Equals cmplx2}"

cmplx2.re <- 4.0

printfn $"{cmplx1} = {cmplx2}: {cmplx1 = cmplx2}"
printfn $"{cmplx1} = {cmplx2}: {cmplx1.Equals cmplx2}"

// The example displays the following output:
//       (4, 1) <> (2, 1): True
//       (4, 1) = (2, 1): False
//       (4, 1) = (4, 1): True
//       (4, 1) = (4, 1): True

Public Structure Complex
    Public re, im As Double
    
    Public Overrides Function Equals(ByVal obj As [Object]) As Boolean 
        Return TypeOf obj Is Complex AndAlso Me = CType(obj, Complex)
    End Function 
    
    Public Overrides Function GetHashCode() As Integer 
        Return Tuple.Create(re, im).GetHashCode()
    End Function 
    
    Public Shared Operator = (x As Complex, y As Complex) As Boolean
       Return x.re = y.re AndAlso x.im = y.im
    End Operator 
    
    Public Shared Operator <> (x As Complex, y As Complex) As Boolean
       Return Not (x = y)
    End Operator 
    
    Public Overrides Function ToString() As String
       Return String.Format("({0}, {1})", re, im)
    End Function 
End Structure

Class Example
   Public Shared Sub Main() 
      Dim cmplx1, cmplx2 As Complex
        
      cmplx1.re = 4.0
      cmplx1.im = 1.0
        
      cmplx2.re = 2.0
      cmplx2.im = 1.0

      Console.WriteLine("{0} <> {1}: {2}", cmplx1, cmplx2, cmplx1 <> cmplx2)        
      Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2))        
      
      cmplx2.re = 4.0
        
      Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1 = cmplx2)        
      Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2))        
   End Sub
End Class 
' The example displays the following output:
'       (4, 1) <> (2, 1): True
'       (4, 1) = (2, 1): False
'       (4, 1) = (4, 1): True
'       (4, 1) = (4, 1): True

Because Complex is a value type, it cannot be derived from. Therefore, the override to Equals(Object) method need not call GetType to determine the precise run-time type of each object, but can instead use the is operator in C# or the TypeOf operator in Visual Basic to check the type of the obj parameter.

Remarks

The type of comparison between the current instance and the obj parameter depends on whether the current instance is a reference type or a value type.

• If the current instance is a reference type, the Equals(Object) method tests for reference equality, and a call to the Equals(Object) method is equivalent to a call to the ReferenceEquals method. Reference equality means that the object variables that are compared refer to the same object. The following example illustrates the result of such a comparison. It defines a Person class, which is a reference type, and calls the Person class constructor to instantiate two new Person objects, person1a and person2, which have the same value. It also assigns person1a to another object variable, person1b. As the output from the example shows, person1a and person1b are equal because they reference the same object. However, person1a and person2 are not equal, although they have the same value.

  using System;
  
  // Define a reference type that does not override Equals.
  public class Person
  {
     private string personName;
  
     public Person(string name)
     {
        this.personName = name;
     }
  
     public override string ToString()
     {
        return this.personName;
     }
  }
  
  public class Example
  {
     public static void Main()
     {
        Person person1a = new Person("John");
        Person person1b = person1a;
        Person person2 = new Person(person1a.ToString());
  
        Console.WriteLine("Calling Equals:");
        Console.WriteLine("person1a and person1b: {0}", person1a.Equals(person1b));
        Console.WriteLine("person1a and person2: {0}", person1a.Equals(person2));
  
        Console.WriteLine("\nCasting to an Object and calling Equals:");
        Console.WriteLine("person1a and person1b: {0}", ((object) person1a).Equals((object) person1b));
        Console.WriteLine("person1a and person2: {0}", ((object) person1a).Equals((object) person2));
     }
  }
  // The example displays the following output:
  //       person1a and person1b: True
  //       person1a and person2: False
  //
  //       Casting to an Object and calling Equals:
  //       person1a and person1b: True
  //       person1a and person2: False
  

  // Define a reference type that does not override Equals.
  type Person(name) =
      override _.ToString() =
          name
  
  let person1a = Person "John"
  let person1b = person1a
  let person2 = Person(string person1a)
  
  printfn "Calling Equals:"
  printfn $"person1a and person1b: {person1a.Equals person1b}"
  printfn $"person1a and person2: {person1a.Equals person2}"
  
  printfn "\nCasting to an Object and calling Equals:"
  printfn $"person1a and person1b: {(person1a :> obj).Equals(person1b :> obj)}"
  printfn $"person1a and person2: {(person1a :> obj).Equals(person2 :> obj)}"
  // The example displays the following output:
  //       person1a and person1b: True
  //       person1a and person2: False
  //
  //       Casting to an Object and calling Equals:
  //       person1a and person1b: True
  //       person1a and person2: False
  

  ' Define a reference type that does not override Equals.
  Public Class Person
     Private personName As String
     
     Public Sub New(name As String)
        Me.personName = name
     End Sub
     
     Public Overrides Function ToString() As String
        Return Me.personName
     End Function 
  End Class
  
  Module Example
     Public Sub Main()
        Dim person1a As New Person("John")
        Dim person1b As Person = person1a
        Dim person2 As New Person(person1a.ToString())
        
        Console.WriteLine("Calling Equals:") 
        Console.WriteLine("person1a and person1b: {0}", person1a.Equals(person1b))               
        Console.WriteLine("person1a and person2: {0}", person1a.Equals(person2))  
        Console.WriteLine()
        
        Console.WriteLine("Casting to an Object and calling Equals:")
        Console.WriteLine("person1a and person1b: {0}", CObj(person1a).Equals(CObj(person1b)))
        Console.WriteLine("person1a and person2: {0}", CObj(person1a).Equals(CObj(person2))) 
     End Sub
  End Module
  ' The example displays the following output:
  '       Calling Equals:
  '       person1a and person1b: True
  '       person1a and person2: False
  '       
  '       Casting to an Object and calling Equals:
  '       person1a and person1b: True
  '       person1a and person2: False
  

• If the current instance is a value type, the Equals(Object) method tests for value equality. Value equality means the following:

  • The two objects are of the same type. As the following example shows, a Byte object that has a value of 12 does not equal an Int32 object that has a value of 12, because the two objects have different run-time types.

    byte value1 = 12;
    int value2 = 12;
    
    object object1 = value1;
    object object2 = value2;
    
    Console.WriteLine("{0} ({1}) = {2} ({3}): {4}",
                      object1, object1.GetType().Name,
                      object2, object2.GetType().Name,
                      object1.Equals(object2));
    
    // The example displays the following output:
    //        12 (Byte) = 12 (Int32): False
    

    let value1 = 12uy
    let value2 = 12
    
    let object1 = value1 :> obj
    let object2 = value2 :> obj
    
    printfn $"{object1} ({object1.GetType().Name}) = {object2} ({object2.GetType().Name}): {object1.Equals object2}"
    
    // The example displays the following output:
    //        12 (Byte) = 12 (Int32): False
    

    Module Example
       Public Sub Main()
          Dim value1 As Byte = 12
          Dim value2 As Integer = 12
          
          Dim object1 As Object = value1
          Dim object2 As Object = value2
          
          Console.WriteLine("{0} ({1}) = {2} ({3}): {4}",
                            object1, object1.GetType().Name,
                            object2, object2.GetType().Name,
                            object1.Equals(object2))
       End Sub
    End Module
    ' The example displays the following output:
    '       12 (Byte) = 12 (Int32): False
    

  • The values of the public and private fields of the two objects are equal. The following example tests for value equality. It defines a Person structure, which is a value type, and calls the Person class constructor to instantiate two new Person objects, person1 and person2, which have the same value. As the output from the example shows, although the two object variables refer to different objects, person1 and person2 are equal because they have the same value for the private personName field.

    using System;
    
    // Define a value type that does not override Equals.
    public struct Person
    {
       private string personName;
    
       public Person(string name)
       {
          this.personName = name;
       }
    
       public override string ToString()
       {
          return this.personName;
       }
    }
    
    public struct Example
    {
       public static void Main()
       {
          Person person1 = new Person("John");
          Person person2 = new Person("John");
    
          Console.WriteLine("Calling Equals:");
          Console.WriteLine(person1.Equals(person2));
    
          Console.WriteLine("\nCasting to an Object and calling Equals:");
          Console.WriteLine(((object) person1).Equals((object) person2));
       }
    }
    // The example displays the following output:
    //       Calling Equals:
    //       True
    //
    //       Casting to an Object and calling Equals:
    //       True
    

    // Define a value type that does not override Equals.
    [<Struct>]
    type Person(personName: string) =
        override _.ToString() =
            personName
    
    let person1 = Person "John"
    let person2 = Person "John"
    
    printfn "Calling Equals:"
    printfn $"{person1.Equals person2}"
    
    printfn $"\nCasting to an Object and calling Equals:"
    printfn $"{(person1 :> obj).Equals(person2 :> obj)}"
    // The example displays the following output:
    //       Calling Equals:
    //       True
    //
    //       Casting to an Object and calling Equals:
    //       True
    

    ' Define a value type that does not override Equals.
    Public Structure Person
       Private personName As String
       
       Public Sub New(name As String)
          Me.personName = name
       End Sub
       
       Public Overrides Function ToString() As String
          Return Me.personName
       End Function 
    End Structure
    
    Module Example
       Public Sub Main()
          Dim p1 As New Person("John")
          Dim p2 As New Person("John")
          
          Console.WriteLine("Calling Equals:") 
          Console.WriteLine(p1.Equals(p2))
          Console.WriteLine()
          
          Console.WriteLine("Casting to an Object and calling Equals:")
          Console.WriteLine(CObj(p1).Equals(p2))
       End Sub
    End Module
    ' The example displays the following output:
    '       Calling Equals:
    '       True
    '       
    '       Casting to an Object and calling Equals:
    '       True
    

Because the Object class is the base class for all types in the .NET Framework, the Object.Equals(Object) method provides the default equality comparison for all other types. However, types often override the Equals method to implement value equality. For more information, see the Notes for Callers and Notes for Inheritors sections.

Notes for the Windows Runtime

When you call the Equals(Object) method overload on a class in the Windows Runtime, it provides the default behavior for classes that don't override Equals(Object). This is part of the support that the .NET Framework provides for the Windows Runtime (see .NET Framework Support for Windows Store Apps and Windows Runtime). Classes in the Windows Runtime don't inherit Object, and currently don't implement an Equals(Object) method. However, they appear to have ToString, Equals(Object), and GetHashCode methods when you use them in your C# or Visual Basic code, and the .NET Framework provides the default behavior for these methods.

Note

Windows Runtime classes that are written in C# or Visual Basic can override the Equals(Object) method overload.

Notes for Callers

Derived classes frequently override the Object.Equals(Object) method to implement value equality. In addition, types also frequently provide an additional strongly typed overload to the Equals method, typically by implementing the IEquatable<T> interface. When you call the Equals method to test for equality, you should know whether the current instance overrides Object.Equals and understand how a particular call to an Equals method is resolved. Otherwise, you may be performing a test for equality that is different from what you intended, and the method may return an unexpected value.

The following example provides an illustration. It instantiates three StringBuilder objects with identical strings, and then makes four calls to Equals methods. The first method call returns true, and the remaining three return false.

using System;
using System.Text;

public class Example
{
   public static void Main()
   {
      StringBuilder sb1 = new StringBuilder("building a string...");
      StringBuilder sb2 = new StringBuilder("building a string...");

      Console.WriteLine("sb1.Equals(sb2): {0}", sb1.Equals(sb2));
      Console.WriteLine("((Object) sb1).Equals(sb2): {0}",
                        ((Object) sb1).Equals(sb2));
      Console.WriteLine("Object.Equals(sb1, sb2): {0}",
                        Object.Equals(sb1, sb2));

      Object sb3 = new StringBuilder("building a string...");
      Console.WriteLine("\nsb3.Equals(sb2): {0}", sb3.Equals(sb2));
   }
}
// The example displays the following output:
//       sb1.Equals(sb2): True
//       ((Object) sb1).Equals(sb2): False
//       Object.Equals(sb1, sb2): False
//
//       sb3.Equals(sb2): False

open System
open System.Text

let sb1 = StringBuilder "building a string..."
let sb2 = StringBuilder "building a string..."

printfn $"sb1.Equals(sb2): {sb1.Equals sb2}"
printfn $"((Object) sb1).Equals(sb2): {(sb1 :> obj).Equals sb2}"
                  
printfn $"Object.Equals(sb1, sb2): {Object.Equals(sb1, sb2)}"

let sb3 = StringBuilder "building a string..."
printfn $"\nsb3.Equals(sb2): {sb3.Equals sb2}"
// The example displays the following output:
//       sb1.Equals(sb2): True
//       ((Object) sb1).Equals(sb2): False
//       Object.Equals(sb1, sb2): False
//
//       sb3.Equals(sb2): False

Imports System.Text

Module Example
   Public Sub Main()
      Dim sb1 As New StringBuilder("building a string...")
      Dim sb2 As New StringBuilder("building a string...")
      
      Console.WriteLine("sb1.Equals(sb2): {0}", sb1.Equals(sb2))
      Console.WriteLine("CObj(sb1).Equals(sb2): {0}", 
                        CObj(sb1).Equals(sb2))
      Console.WriteLine("Object.Equals(sb1, sb2): {0}",
                        Object.Equals(sb1, sb2))                  
      
      Console.WriteLine()
      Dim sb3 As Object = New StringBuilder("building a string...")
      Console.WriteLine("sb3.Equals(sb2): {0}", sb3.Equals(sb2))                              
   End Sub
End Module
' The example displays the following output:
'       sb1.Equals(sb2): True
'       CObj(sb1).Equals(sb2): False
'       Object.Equals(sb1, sb2): False
'
'       sb3.Equals(sb2): False

In the first case, the strongly typed StringBuilder.Equals(StringBuilder) method overload, which tests for value equality, is called. Because the strings assigned to the two StringBuilder objects are equal, the method returns true. However, StringBuilder does not override Object.Equals(Object). Because of this, when the StringBuilder object is cast to an Object, when a StringBuilder instance is assigned to a variable of type Object, and when the Object.Equals(Object, Object) method is passed two StringBuilder objects, the default Object.Equals(Object) method is called. Because StringBuilder is a reference type, this is equivalent to passing the two StringBuilder objects to the ReferenceEquals method. Although all three StringBuilder objects contain identical strings, they refer to three distinct objects. As a result, these three method calls return false.

You can compare the current object to another object for reference equality by calling the ReferenceEquals method. In Visual Basic, you can also use the is keyword (for example, If Me Is otherObject Then ...).

Notes for Inheritors

When you define your own type, that type inherits the functionality defined by the Equals method of its base type. The following table lists the default implementation of the Equals method for the major categories of types in the .NET Framework.

For a value type, you should always override Equals, because tests for equality that rely on reflection offer poor performance. You can also override the default implementation of Equals for reference types to test for value equality instead of reference equality and to define the precise meaning of value equality. Such implementations of Equals return true if the two objects have the same value, even if they are not the same instance. The type's implementer decides what constitutes an object's value, but it is typically some or all the data stored in the instance variables of the object. For example, the value of a String object is based on the characters of the string; the String.Equals(Object) method overrides the Object.Equals(Object) method to return true for any two string instances that contain the same characters in the same order.

The following example shows how to override the Object.Equals(Object) method to test for value equality. It overrides the Equals method for the Person class. If Person accepted its base class implementation of equality, two Person objects would be equal only if they referenced a single object. However, in this case, two Person objects are equal if they have the same value for the Person.Id property.

public class Person
{
   private string idNumber;
   private string personName;

   public Person(string name, string id)
   {
      this.personName = name;
      this.idNumber = id;
   }

   public override bool Equals(Object obj)
   {
      Person personObj = obj as Person;
      if (personObj == null)
         return false;
      else
         return idNumber.Equals(personObj.idNumber);
   }

   public override int GetHashCode()
   {
      return this.idNumber.GetHashCode();
   }
}

public class Example
{
   public static void Main()
   {
      Person p1 = new Person("John", "63412895");
      Person p2 = new Person("Jack", "63412895");
      Console.WriteLine(p1.Equals(p2));
      Console.WriteLine(Object.Equals(p1, p2));
   }
}
// The example displays the following output:
//       True
//       True

open System

type Person(name, id) =
    member _.Name = name
    member _.Id = id

    override _.Equals(obj) =
        match obj with
        | :? Person as personObj ->
            id.Equals personObj.Id
        | _ -> 
            false

    override _.GetHashCode() =
        id.GetHashCode()

let p1 = Person("John", "63412895")
let p2 = Person("Jack", "63412895")
printfn $"{p1.Equals p2}"
printfn $"{Object.Equals(p1, p2)}"
// The example displays the following output:
//       True
//       True

Public Class Person
   Private idNumber As String
   Private personName As String
   
   Public Sub New(name As String, id As String)
      Me.personName = name
      Me.idNumber = id
   End Sub
   
   Public Overrides Function Equals(obj As Object) As Boolean
      Dim personObj As Person = TryCast(obj, Person) 
      If personObj Is Nothing Then
         Return False
      Else
         Return idNumber.Equals(personObj.idNumber)
      End If   
   End Function
   
   Public Overrides Function GetHashCode() As Integer
      Return Me.idNumber.GetHashCode() 
   End Function
End Class

Module Example
   Public Sub Main()
      Dim p1 As New Person("John", "63412895")
      Dim p2 As New Person("Jack", "63412895")
      Console.WriteLine(p1.Equals(p2))
      Console.WriteLine(Object.Equals(p1, p2))
   End Sub
End Module
' The example displays the following output:
'       True
'       True

In addition to overriding Equals, you can implement the IEquatable<T> interface to provide a strongly typed test for equality.

The following statements must be true for all implementations of the Equals(Object) method. In the list, x, y, and z represent object references that are not null.

• x.Equals(x) returns true.

• x.Equals(y) returns the same value as y.Equals(x).

• x.Equals(y) returns true if both x and y are NaN.

• If (x.Equals(y) && y.Equals(z)) returns true, then x.Equals(z) returns true.

• Successive calls to x.Equals(y) return the same value as long as the objects referenced by x and y are not modified.

• x.Equals(null) returns false.

Implementations of Equals must not throw exceptions; they should always return a value. For example, if obj is null, the Equals method should return false instead of throwing an ArgumentNullException.

Follow these guidelines when overriding Equals(Object):

• Types that implement IComparable must override Equals(Object).

• Types that override Equals(Object) must also override GetHashCode; otherwise, hash tables might not work correctly.

• You should consider implementing the IEquatable<T> interface to support strongly typed tests for equality. Your IEquatable<T>.Equals implementation should return results that are consistent with Equals.

• If your programming language supports operator overloading and you overload the equality operator for a given type, you must also override the Equals(Object) method to return the same result as the equality operator. This helps ensure that class library code that uses Equals (such as ArrayList and Hashtable) behaves in a manner that is consistent with the way the equality operator is used by application code.

Guidelines for Reference Types

The following guidelines apply to overriding Equals(Object) for a reference type:

• Consider overriding Equals if the semantics of the type are based on the fact that the type represents some value(s).

• Most reference types must not overload the equality operator, even if they override Equals. However, if you are implementing a reference type that is intended to have value semantics, such as a complex number type, you must override the equality operator.

• You should not override Equals on a mutable reference type. This is because overriding Equals requires that you also override the GetHashCode method, as discussed in the previous section. This means that the hash code of an instance of a mutable reference type can change during its lifetime, which can cause the object to be lost in a hash table.

Guidelines for Value Types

The following guidelines apply to overriding Equals(Object) for a value type:

• If you are defining a value type that includes one or more fields whose values are reference types, you should override Equals(Object). The Equals(Object) implementation provided by ValueType performs a byte-by-byte comparison for value types whose fields are all value types, but it uses reflection to perform a field-by-field comparison of value types whose fields include reference types.

• If you override Equals and your development language supports operator overloading, you must overload the equality operator.

• You should implement the IEquatable<T> interface. Calling the strongly typed IEquatable<T>.Equals method avoids boxing the obj argument.

See also

• ReferenceEquals(Object, Object)
• GetHashCode()
• ValueType
• IComparable
• ArrayList
• Hashtable

Applies to

Equals(Object, Object)

Determines whether the specified object instances are considered equal.

public:
 static bool Equals(System::Object ^ objA, System::Object ^ objB);

public static bool Equals (object objA, object objB);

public static bool Equals (object? objA, object? objB);

static member Equals : obj * obj -> bool

Public Shared Function Equals (objA As Object, objB As Object) As Boolean

Parameters

objA Object

The first object to compare.

objB Object

The second object to compare.

Returns

true if the objects are considered equal; otherwise, false. If both objA and objB are null, the method returns true.

Examples

The following example illustrates the Equals(Object, Object) method and compares it with the ReferenceEquals method.

using System;

public class Example
{
   public static void Main()
   {
      Dog m1 = new Dog("Alaskan Malamute");
      Dog m2 = new Dog("Alaskan Malamute");
      Dog g1 = new Dog("Great Pyrenees");
      Dog g2 = g1;
      Dog d1 = new Dog("Dalmation");
      Dog n1 = null;
      Dog n2 = null;

      Console.WriteLine("null = null: {0}", Object.Equals(n1, n2));
      Console.WriteLine("null Reference Equals null: {0}\n", Object.ReferenceEquals(n1, n2));

      Console.WriteLine("{0} = {1}: {2}", g1, g2, Object.Equals(g1, g2));
      Console.WriteLine("{0} Reference Equals {1}: {2}\n", g1, g2, Object.ReferenceEquals(g1, g2));

      Console.WriteLine("{0} = {1}: {2}", m1, m2, Object.Equals(m1, m2));
      Console.WriteLine("{0} Reference Equals {1}: {2}\n", m1, m2, Object.ReferenceEquals(m1, m2));

      Console.WriteLine("{0} = {1}: {2}", m1, d1, Object.Equals(m1, d1));
      Console.WriteLine("{0} Reference Equals {1}: {2}", m1, d1, Object.ReferenceEquals(m1, d1));
   }
}

public class Dog
{
   // Public field.
   public string Breed;

   // Class constructor.
   public Dog(string dogBreed)
   {
      this.Breed = dogBreed;
   }

   public override bool Equals(Object obj)
   {
      if (obj == null || !(obj is Dog))
         return false;
      else
         return this.Breed == ((Dog) obj).Breed;
   }

   public override int GetHashCode()
   {
      return this.Breed.GetHashCode();
   }

   public override string ToString()
   {
      return this.Breed;
   }
}
// The example displays the following output:
//       null = null: True
//       null Reference Equals null: True
//
//       Great Pyrenees = Great Pyrenees: True
//       Great Pyrenees Reference Equals Great Pyrenees: True
//
//       Alaskan Malamute = Alaskan Malamute: True
//       Alaskan Malamute Reference Equals Alaskan Malamute: False
//
//       Alaskan Malamute = Dalmation: False
//       Alaskan Malamute Reference Equals Dalmation: False

open System

// Class constructor
type Dog(dogBreed) =
    // Public property.
    member _.Breed = dogBreed

    override this.Equals(obj) =
        match obj with
        | :? Dog as dog when dog.Breed = this.Breed -> true
        | _ -> false

    override _.GetHashCode() =
        dogBreed.GetHashCode()

    override _.ToString() =
        dogBreed

let m1 = Dog "Alaskan Malamute"
let m2 = Dog "Alaskan Malamute"
let g1 = Dog "Great Pyrenees"
let g2 = g1
let d1 = Dog "Dalmation"
let n1 = Unchecked.defaultof<Dog>
let n2 = Unchecked.defaultof<Dog>

printfn $"null = null: {Object.Equals(n1, n2)}"
printfn $"null Reference Equals null: {Object.ReferenceEquals(n1, n2)}\n"

printfn $"{g1} = {g2}: {Object.Equals(g1, g2)}"
printfn $"{g1} Reference Equals {g2}: {Object.ReferenceEquals(g1, g2)}\n"

printfn $"{m1} = {m2}: {Object.Equals(m1, m2)}"
printfn $"{m1} Reference Equals {m2}: {Object.ReferenceEquals(m1, m2)}\n"

printfn $"{m1} = {d1}: {Object.Equals(m1, d1)}"
printfn $"{m1} Reference Equals {d1}: {Object.ReferenceEquals(m1, d1)}"

// The example displays the following output:
//       null = null: True
//       null Reference Equals null: True
//
//       Great Pyrenees = Great Pyrenees: True
//       Great Pyrenees Reference Equals Great Pyrenees: True
//
//       Alaskan Malamute = Alaskan Malamute: True
//       Alaskan Malamute Reference Equals Alaskan Malamute: False
//
//       Alaskan Malamute = Dalmation: False
//       Alaskan Malamute Reference Equals Dalmation: False

Module Example
   Public Sub Main()
      Dim m1 As New Dog("Alaskan Malamute")
      Dim m2 As New Dog("Alaskan Malamute")
      Dim g1 As New Dog("Great Pyrenees")
      Dim g2 As Dog = g1
      Dim d1 As New Dog("Dalmation")
      Dim n1 As Dog = Nothing
      Dim n2 As Dog = Nothing
      
      Console.WriteLine("null = null: {0}", Object.Equals(n1, n2))
      Console.WriteLine("null Reference Equals null: {0}", Object.ReferenceEquals(n1, n2))
      Console.WriteLine()
      
      Console.WriteLine("{0} = {1}: {2}", g1, g2, Object.Equals(g1, g2))
      Console.WriteLine("{0} Reference Equals {1}: {2}", g1, g2, Object.ReferenceEquals(g1, g2))
      Console.WriteLine()
      
      Console.WriteLine("{0} = {1}: {2}", m1, m2, Object.Equals(m1, m2))
      Console.WriteLine("{0} Reference Equals {1}: {2}", m1, m2, Object.ReferenceEquals(m1, m2))
      Console.WriteLine()
      
      Console.WriteLine("{0} = {1}: {2}", m1, d1, Object.Equals(m1, d1))  
      Console.WriteLine("{0} Reference Equals {1}: {2}", m1, d1, Object.ReferenceEquals(m1, d1))  
   End Sub
End Module

Public Class Dog
   ' Public field.
   Public Breed As String
   
   ' Class constructor.
   Public Sub New(dogBreed As String)
      Me.Breed = dogBreed
   End Sub

   Public Overrides Function Equals(obj As Object) As Boolean
      If obj Is Nothing OrElse Not typeof obj Is Dog Then
         Return False
      Else
         Return Me.Breed = CType(obj, Dog).Breed
      End If   
   End Function
   
   Public Overrides Function GetHashCode() As Integer
      Return Me.Breed.GetHashCode()
   End Function
   
   Public Overrides Function ToString() As String
      Return Me.Breed
   End Function
End Class
' The example displays the following output:
'       null = null: True
'       null Reference Equals null: True
'       
'       Great Pyrenees = Great Pyrenees: True
'       Great Pyrenees Reference Equals Great Pyrenees: True
'       
'       Alaskan Malamute = Alaskan Malamute: True
'       Alaskan Malamute Reference Equals Alaskan Malamute: False
'       
'       Alaskan Malamute = Dalmation: False
'       Alaskan Malamute Reference Equals Dalmation: False

Remarks

The static Equals(Object, Object) method indicates whether two objects, objA and objB, are equal. It also enables you to test objects whose value is null for equality. It compares objA and objB for equality as follows:

• It determines whether the two objects represent the same object reference. If they do, the method returns true. This test is equivalent to calling the ReferenceEquals method. In addition, if both objA and objB are null, the method returns true.

• It determines whether either objA or objB is null. If so, it returns false.

• If the two objects do not represent the same object reference and neither is null, it calls objA.Equals(objB) and returns the result. This means that if objA overrides the Object.Equals(Object) method, this override is called.

See also

• Equals(Object)
• ReferenceEquals(Object, Object)

Applies to

Which of these methods of class string is used to compare two string objects?

Which of these method of class string is used to compare two string objects for their equality Isequal () Isequal () equals () equals ()?

Which is the method of class string that is used to compare two string objects for their equality Mcq?

Which of these method of class string is used to compare two string objects for their equality immersive reader 1 point equals () equals () Isequal () Isequal ()?